10x^2+44x+44=0

Solution for 10x^2+44x+44=0 equation:

10x^2+44x+44=0

a = 10; b = 44; c = +44;
Δ = b2-4ac
Δ = 442-4·10·44
Δ = 176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{176}=\sqrt{16*11}=\sqrt{16}*\sqrt{11}=4\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-4\sqrt{11}}{2*10}=\frac{-44-4\sqrt{11}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+4\sqrt{11}}{2*10}=\frac{-44+4\sqrt{11}}{20}
$